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iogann1982 [59]
4 years ago
10

52.46 round to the nearest one

Mathematics
2 answers:
borishaifa [10]4 years ago
8 0
I believe the answer is 53 let me know :) 
kykrilka [37]4 years ago
7 0
To the nearest would be about 52
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How many times larger is the 8 in 184.36 than 9,027.83
Sunny_sXe [5.5K]

Answer: Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.

Step-by-step explanation:

First we can find out the place value,

Then we can write,

Define Place value :

Place value is the basis of our entire number system. This is the system in which the position of a digit in a number determines its value. The number 42,316 is different from 61,432 because the digits are in different positions.

                     [or]

Place value of a digit can be defined as the position of the particular digit in a given number.

For Example :

The place value of 7 in 1870 is  70

Given the data,

First we use digit is :    184.36

Second we use digit is : 9027.83

Place value of 8 in First digit is  ⇒ 184.36 is 80

Place value of 8 in Second digit is ⇒ 9027.83  is 0. 8

We can solve the Ratio is :

                      Ratio = 80/ 0.8

                       Ratio = 100 times

Therefore,

Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.

Learn more about event correlation here: brainly.com/question/17103145

#SPJ9

4 0
2 years ago
Keesha Thompsons cousin is 8 years older than keesha. Write an expression for the age of keesha's cousin
Oliga [24]

Answer:

y = 8 + x or

Keesha.cousin.age = 8 + Keesha.age

Step-by-step explanation:

II. When Keesha.cousin is older than Keesha 8 years

    Give y = 8 + x, when y is Keesha cousin.age, x is Keesha.age

            y = 8 + x

II. Prove by given Keesha is 10 years old.

            y = 8 + 10

            y = 18 or Keesha cousin is 18 years old.

Hope that help :)

3 0
3 years ago
Let Y1 and Y2 be independent exponentially distributed random variables, each with mean 7. Find P(Y1 > Y2 | Y1 < 2Y2). (En
ArbitrLikvidat [17]

<em>Y</em>₁ and <em>Y</em>₂ are independent, so their joint density is

f_{Y_1,Y_2}(y_1,y_2)=f_{Y_1}(y_1)f_{Y_2}(y_2)=\begin{cases}\frac1{49}e^{-\frac{y_1+y_2}7}&\text{for }y_1\ge0,y_2\ge0\\0&\text{otherwise}\end{cases}

By definition of conditional probability,

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = P((<em>Y</em>₁ > <em>Y</em>₂) and (<em>Y</em>₁ < 2 <em>Y</em>₂)) / P(<em>Y</em>₁ < 2 <em>Y</em>₂)

Use the joint density to compute the component probabilities:

• numerator:

P((Y_1>Y_2)\text{ and }(Y_1

=\displaystyle\frac1{49}\int_0^\infty\int_{\frac{y_1}2}^{y_1}e^{-\frac{y_1+y_2}7}\,\mathrm dy_2\,\mathrm dy_1

=\displaystyle-\frac17\int_0^\infty\int_{-\frac{3y_1}{14}}^{-\frac{2y_1}7}e^u\,\mathrm du\,\mathrm dy_1

=\displaystyle-\frac17\int_0^\infty\left(e^{-\frac{2y_1}7} - e^{-\frac{3y_1}{14}}\right)\,\mathrm dy_1

=\displaystyle-\frac17\left(-\frac72e^{-\frac{2y_1}7} + \frac{14}3 e^{-\frac{3y_1}{14}}\right)\bigg|_0^\infty

=\displaystyle-\frac17\left(\frac72 - \frac{14}3\right)=\frac16

• denominator:

P(Y_1

(I leave the details of the second integral to you)

Then you should end up with

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = (1/6) / (2/3) = 1/4

5 0
3 years ago
A spinner is divided into 15 identical sectors and labeled 1 through 15.
Papessa [141]
I’m not sure i’m pretty sure it’s 28
6 0
2 years ago
Read 2 more answers
What is the density of water? Remember for water 1g=1ml=1cm^3
NeTakaya

Answer:

1 g/cm^3 or 1 g/ml

Step-by-step explanation:


5 0
3 years ago
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