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prohojiy [21]
3 years ago
6

I don’t understand this at all please help

Mathematics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

You need 10 of those numbers to be whole numbers, decimals, or fractions (THESE ARE RATIONAL)

You need the other 10 of those numbers to radicals, or numbers similar to pi (THESE ARE IRRATIONAL)

Step-by-step explanation:

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An acute angle measures less than π/2 but greater than 0
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If you're looking for an angle in between those, basically you have to choose an angle between 0 and 90°. any angle should work (such as 15°, 45°, 60°, 75°, etc.)
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What is the opposite of the opposite of the number located at point a?<br> ght
den301095 [7]
Its c (9) because the opposite of -9 is 9
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3 years ago
A triangle can be formed with side lengths 2in, 3in and 6 in?<br>true or false?​
Aleks04 [339]

Answer:

No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.

For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.

2

in.

+

3

in.

=

5

in.

5

in.

<

6

in.

For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:

3 + 4 = 7 which is greater than 5

3 + 5 = 8 which is greater than 4

4 + 5 = 9 which is greater than 3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The general form of an parabola is 2x2−12x−3y+12=0 .
Murljashka [212]

Answer:

The standard form of the parabola is (x-3)^2=4*\frac{3}{8}(y+2)

Step-by-step explanation:

The standard form of a parabola is

(x-h)^2=4p(y-k).

In order to convert 2x^2-12x-3y+12=0 into the standard form, we first separate the variables:

2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y

we now divided both sides by 2 to remove the coefficient from 2x^2 and get:

x^2-6x+6=\frac{3}{2}y.

We complete the square on the left side by adding 3 to both sides:

x^2-6x+6+3=\frac{3}{2}y+3

x^2-6x+9=\frac{3}{2}y+3

(x-3)^2=\frac{3}{2}y+3

now we bring the right side into the form 4p(y-k) by first multiplying the equation by \frac{2}{3}:

\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2

and then we multiplying both sides by \frac{3}{2} to get

(x-3)^2=\frac{3}{2} (y+2).

Here we see that

4p=\frac{3}{2}

\therefore p=\frac{3}{8}

Thus, finally we have the equation of the parabola in the standard form:

\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}

5 0
3 years ago
3a+2(b+5a) plz answer this <br> I really tryied but noap I keep on get in it wrong
PilotLPTM [1.2K]
Answer is 13a + 2b multiply everything in the parenthesis by 2 so 2 x b is 2b and 2 x 5a is 10a so 3a + 10a is 13a + 2b
8 0
3 years ago
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