The answer is -a + b = 0
If she wants to solve <span>a system of linear equations by elimination and if one equation is unknown, one of the solutions in the unknown equation must be negative:
Known equation: a + b = 4
Unknown equation: -a + b = ?
We know that a = 2 and be = 2, thus:
</span>Unknown equation: -2 + 2 = 0
The general form of the equation is -a + b = 0
Let's check it out:
Known equation: a + b = 4
Unknown equation: -a + b = 0
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Add them up: 2b = 4
b = 4/2 = 2
a + b = 4
a = 4 - b
a = 4 - 2
a = 2
So, the second equation is correct.
Answer: 81a^8b^12
Step-by-step explanation:
When you have an exponent to an exponent multiply the exponents.
(3a^2b^3)^4
=81a^8b^12
Ed
To do this problem, you need to raise each of the individual terms inside the parentheses
to the 4th power.
In other words:
Now you can recognize that 3%5E4 is 3*3*3*3 and this product is 81. So you can substitute
81 in place of 3%5E4 and the problem is reduced to:
.
81%2A%28a%5E2%29%5E4%2A+%28b%5E3%29%5E4
.
Next look at %28a%5E2%29%5E4. You can get an equivalent form of this by multiplying the exponent
4 by the exponent 2 to get a%5E8. You can also think of %28a%5E2%29%5E4 as being a%5E2
To solve this, what you will need to do is find the solution of one variable and then substitute it and solve for the other.
Here’s how to solve:
y+2x=4
-2x -2x
y=4-2x
4-2x + 2x =4
4=4
So if you’re trying to see if it is true, then your answer is that it’s true.
If you’re trying to find the linear equation, then your answer is y=-2x+4.
Answer:
(c) 8x^2 -32x +32, repeated root is x=2.
Step-by-step explanation:
A quadratic with repeated roots will be a multiple of a perfect square trinomial. The form of it will be ...
a(x -b)² = ax² -2abx +ab² = a(x² -2bx +b²)
Dividing by the leading coefficient will leave a monic quadratic whose constant is a (positive) perfect square, and whose linear term has a coefficient that is double the root of the constant.
__
<h3>-x^2 + 18x + 81</h3>
Dividing by the leading coefficient gives ...
x^2 -18x -81 . . . . . a negative constant
__
<h3>3x^2 - 6x + 9</h3>
Dividing by the leading coefficient gives ...
x^2 -2x +3 . . . . . . constant is not a perfect square
__
<h3>8x^2 - 32x + 32</h3>
Dividing by the leading coefficient gives ...
x^2 -4x +4 = (x -2)^2 . . . . . has a repeated root of x=2
__
<h3>25x^2 - 30x - 9</h3>
Dividing by the leading coefficient gives ...
x^2 -1.2x -0.36 . . . . . . a negative constant
__
<h3>x^2 - 14x + 196</h3>
The x-coefficient is not 2 times the root of the constant.
14 = √196 ≠ 2√196
Answer:
ertcfdrsdvsfrgvgerceqrwvr
Step-by-step explanation: