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3 years ago

Which segment shows the cyclist stopping for a drink of water?

1 answer:

8 0

The only way to properly answer your question is with the image, but without it, I can still give you a guess of what it will be.

Generally, with these types of problems, the cyclist will begin riding at an increasingly fast pace, Then they will begin slowing down, so the line decreases. When he stops for water the line should remain constant. Meaning a straight horizontal line such as this ------------------

If you can include an image I can give you the exact answer you're looking for, however.

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3 years ago

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A snack bar weighs 61g, and 10% of the weight is apple. How many

eduard

Answer:

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2 years ago

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Does someone know the answer to this <br> √7x+16+4=x

dalvyx [7]

I think it is 54.332

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3 years ago

Help with this question ??

NNADVOKAT [17]

Answer: 12 tables minimum, 15 max.

Step-by-step explanation:

If you substitute 14 in an inequality

200c + 500t >= 8800

200(14) + 500t and solve for t, you get t must be at least 12.

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So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.

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3 years ago

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.

n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p= $-0. 4t^2+128t+1,200$

For population to disappear, p =0

$-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115$

But t = -9.115 is not possible as time cannot be negative

So, the owl population will disappear after 329.12 years

To learn more about quadratic equation, refer to the link-

brainly.com/question/1214333

#SPJ4

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1 year ago