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3 years ago

Equivalent expressions to -90x+60

Mathematics

1 answer:

melomori [17]3 years ago

4 0

60+-90x would be equivalent.

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Which criterion can be used to prove ABC and ADC are congruent?

olya-2409 [2.1K]

Triangles have common side AC, and 2 adjacent to this side corresponding angles.
∠BAC=∠DCA, and
∠ACB=∠SAD.
So, triangles <span>ABC and ADC are congruent by ASA.</span>

8 0

3 years ago

PLEASE HELP ME!! How do you solve??

Fudgin [204]

Number 4 is 1
3-x = -x + 3

7 0

2 years ago

Write 6,392,094,003 in word form

sattari [20]

Six billion three hundred ninety-two million ninety-four thousand and three

6 0

3 years ago

Read 2 more answers

If you bought your car 5 years ago for $15,000 and today you can sell for $7000, what was it's rate of depreciation? Round to tw

serg [7]

Answer : The rate of depreciation is, $16000

Step-by-step explanation :

Formula used to calculate the rate of depreciation is:

$\text{Depreciation rate}=\frac{\text{Purchase price of asset }+\text{ Salvage value}}{\text{Estimate life of asset}}$

Given:

Purchase price of asset = $15000

Salvage value = $7000

Estimate life asset = 3 years

Now put all the given values in the above formula, we get:

$\text{Depreciation rate}=\frac{15000+7000}{5}$

Deprecation rate = $16000

Therefore, the rate of depreciation is, $16000

5 0

3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago