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Stolb23 [73]
3 years ago
13

I beg please help :(

Mathematics
1 answer:
Aloiza [94]3 years ago
6 0

Answer:

(2.8, 0.8)

(0.8, -1.8)

Step-by-step explanation:

1. Home (Xa, Ya)= (8, 6)

San Antonio (Xb, Yb)=(-5, -7)

Xa-Xb=8-(-5)=13

Ya-Yb=6-(-7)=13

Emily  starts at 2/5 of the road, make it  (Xc, Yc)

Xc= Xa-(Xa-Xb)2/5=8-5.2=2.8

Yc=Ya-(Ya-Yb)2/5=6-5.2=0.8

=> Emily starts at (2.8, 0.8)

2.

Emily ends at 3/5 of the road, , make it  (Xd, Yd)

Xd= Xa-(Xa-Xb)3/5=8-7.8=0.8

Yd=Ya-(Ya-Yb)3/5=6-7.8=-1.8

=> Emily ends at (0.8, -1.8)

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Answer:

0.055 = 5.5% probability that exactly 5 employees were over 50.

Step-by-step explanation:

The employees are removed from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

7 + 18 = 25 employees, which means that N = 25

7 over 50, which means that k = 7

10 dismissed, which means that n = 10

What is the probability that exactly 5 employees were over 50?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,25,10,7) = \frac{C_{7,5}*C_{18,5}}{C_{25,10}} = 0.055

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5 0
2 years ago
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dmitriy555 [2]

Answer:

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Step-by-step explanation:

12c - 53= 91

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<em>Hope it helps <3</em>

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