All categories

3 years ago

4. Calculate the product of 8/15, 645, and 1/3. A. 48/15 B. 48/30 C. 16/75 D. 18/15

Mathematics

1 answer:

DaniilM [7]3 years ago

3 0

Answer:

645.866 or 646

Step-by-step explanation:

645.866 is the sum of 8/15+ 645/1 +1/3

1/3 = 0.333 + 8/15 = 0.533 = 0.866

645+ 0.866= 645.866

If we are asked to round these to units

we have 646

You might be interested in

Write a number in each blank to complete each equation so that it has the requested number of solutions. a. Equation with no sol

Setler79 [48]

Answer:

The answer is 8 $x$ - 3 $x$ + 2 - $x$ = 4  $x$ + 2  .

Step-by-step explanation:

Given:

8x - 3x + 2 -x = __ x + __

Now, to write a number in each blank to complete each equation so that it has the requested number of solutions.

So, to solve the equation:

$8x-3x+2-x$

So, we add the variables:

$5x+2-x$

And, then subtract it:

$4x-2.$

Thus, it remains:

$4x-2$ .

So the complete equation is:

8 $x$ - 3 $x$ + 2 - $x$ = 4 $x$ + 2

Therefore, the answer is 8 $x$ - 3 $x$ + 2 - $x$ = 4  $x$ + 2  .

4 0

3 years ago

Do you like cake or ice cream more?

jenyasd209 [6]

Answer:

ice cream no no

Step-by-step explanation:

ice cream good i dont like the smell i am not bored

4 0

3 years ago

Read 2 more answers

15 POINTS!

joja [24]

8x + (2x - 14)= 7x + 3x -14

10x -14= 10x - 14

These equations are identical, so it would be the identity property and the answer would either be identity or the fancy 'R'.

6 0

3 years ago

Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

3 years ago

The quotient of y and 8 is greater than 10

goldenfox [79]

Answer:

Well the ineqaulity here would be

y/8 > 10

Or in simpler terms

y ÷ 8 > 10

If you were to solve

y > 80

4 0

3 years ago