Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :

A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : 

A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : 

A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :

A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Answer: 85
Step-by-step explanation: 15 × 6= 90 - 5= 85
Answer:
770000
Step by step explanation:
This is a proportion problem.
z 4
--- = ----
12 5
We can cross multiply and divide.
5z = 48
z = 9.6
Hope this helps!
Answer:
(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.
Step-by-step explanation:
Given



Required
Which circle could she use
To do this, we simply calculate the areas of all the given circles
The area of a circle is:

Where


The area is calculated as thus:





The area is calculated as thus:




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The area is calculated as thus:





The area is calculated as thus:




<em>From the calculations above; only the circle in option (b) has an area within the required range of 135 to 155cm^2</em>