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2 years ago

Which algebraic expression represents the total area of a cube each dimension of which is 1.5x

Mathematics

2 answers:

zepelin [54]2 years ago

8 0

Answer:

okkkkkkkķkkkkkkkkkkkkk

In-s [12.5K]2 years ago

6 0

Answer:

Step 1: Remove parentheses by multiplying factors.

= (x * x) + (1 * x) + (2 * x) + (2 * 1)

Step 2: Combine like terms by adding coefficients.

(x * x) = x2

(1 * x) = 1x

(2* x) = 2x

Step 3: Combine the constants.

(2 * 1) = 2

Step 4: Therefore, Simplifying Algebraic Expression is solved as

= x2 + 3x + 2.

Step-by-step explanation:

A cube is 3- dimensional shape with 6 equal sides, 6 faces, and 6 vertices in geometry. ... In 3 – dimension, the cube's sides are; the length, width, and height.

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Ayooo guys SOMEONE TELL ME WHAT IS THE AWNSER ?

Luden [163]

Answer:

60.......

Explanation:

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2 years ago

an outfielder throws a ball to home plate. the balls path is modeled by the graph of y=x/5-x^2/1000 where x represents the horiz

saul85 [17]

The coordinates of the vertex for the quadratic function are given as follows: (100,10).

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

$y = ax^2 + bx + c$

The vertex is given by:

$(x_v, y_v)$

In which:

$x_v = -\frac{b}{2a}$

$y_v = -\frac{b^2 - 4ac}{4a}$

In this problem, the function is given as follows:

y = -x²/1000 + x/5

y = -0.001x² + 0.2x.

Hence the coefficients are a = -0.001, b = 0.2, c = 0 and the coordinates of the vertex are given as follows:

$x_v = -\frac{0.2}{2(-0.001)} = 100$

$y_v = -\frac{(0.2)^2}{4(-0.001)} = 10$

More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

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4 0

2 years ago

17 points!!<br> Need anyone FAST! Please

guapka [62]

Answer:

80%

Step-by-step explanation:

((y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

((36 - 20) / 20) * 100 = 80 %

3 0

3 years ago

Read 2 more answers

Will mark brainlest how to multipy it

Lesechka [4]

Answer:

$\displaystyle x = 2 \sqrt{3}$

Step-by-step explanation:

we would like to solve the following equation:

$\displaystyle \sqrt{3} = \frac{6}{x}$

in order to do so do cross multiplication:

$\displaystyle x \sqrt{3} = 6$

divide both sides by √3:

$\displaystyle x = \frac{6}{ \sqrt{3}}$

since we ended up with a square root on the denominator so we can consider rationalising the denominator to do so multiply both numerator and denominator by √3 which yields:

$\displaystyle x = \frac{6}{ \sqrt{3}} \times \frac{ \sqrt{3} }{ \sqrt{ 3} }$