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11Alexandr11 [23.1K]
2 years ago
9

Find the domain of the graphed function.

Mathematics
2 answers:
DedPeter [7]2 years ago
8 0

Answer:

Thanks to that other person for helping me understand freshman math rn, something that my high school teachers were never able to do for tree years, this person. Yee

Step-by-step explanation:


nika2105 [10]2 years ago
3 0
For every point on the curve, imagine drawing a vertical line until that vertical line reaches the x axis.

Doing this will essentially shade the x axis number line from x = -4 to x = 2

The graph shows points in which the x coordinate is as small as -4 or as large as 2, or anything in between

Domain: -4 \le x \le 2
Answer: Choice B

note: the domain is the set of allowed inputs or x values
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A movie theater designs two bags to hold 250 cubic inches of popcorn each.
grigory [225]

Answer:

5 inches

Step-by-step explanation:

Well two bags hold 250 cubic inches, which means one bag will hold 125 cubic inches.

Then you cube route 125 because its cubic inches.

\sqrt[3]{125} = 5

So I would think its five inches but I may be wrong <3

4 0
2 years ago
Evaluate 12x-(4y+7z) for x=9 y= 4 and z = 2
Brums [2.3K]

The answer to "12x-(4y+7z) for x=9 y= 4 and z = 2" is 78.

6 0
3 years ago
Simplify and expand (X+3)(x-3)(3x+3)<br>​
ivolga24 [154]

Answer:

3x^3 + 3x^2 - 27x - 27

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
2 years ago
Please help I need help
JulijaS [17]
The rate of change in this pattern is 2:1 comparing the change in 'y' to the change in 'x'.. this means that if you go form 33 to 51 ( an increase of 18), then the the increase from 16 to ? will be 9.  Therefore, ? = 16 + 9 or 25
? = 25
4 0
2 years ago
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