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3 years ago

Tell whether (5, 1) is a solution of y

Mathematics

1 answer:

Arisa [49]3 years ago

7 0

Answer:

1 because Because the right number will be the Y intercept an in the left number will the X interception

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Adding and subtracting the given polynomials

Usimov [2.4K]

You have to combine like terms, so the variable (x, y, s, d, c....) and the exponents must be the same in order to combine them.

For example:

x² + x³ Since they don't have the same exponent, you can't combine them

y² + 3y² = 4y²

23x + x = 24x

4. 2s² + 1 + s² - 2s + 1 You can rearrange it if it makes it easier

2s² + s² - 2s + 1 + 1 = 3s² - 2s + 2

5. 5t² - 2t - 1 - (3t² - 5t + 7) Distribute/multiply the - to (3t² - 5t + 7)

5t² - 2t - 1 - 3t² + 5t - 7 = 2t² + 3t - 8

Do the same for #9 and #10, and you should get:

9. 2k² + 5k - 9

10. 6y³ - 7y² - 6y - 12

3 0

3 years ago

There are 5 black marbles, 17 blue marbles, 10 brown marbles, and 12 white marbles. What is the ratio of white marbles to all th

bogdanovich [222]

Answer:

12:44

Step-by-step explanation:

u would add all the marbles up and then put the white marble amount in front of a colon and then put the total marbles

5 0

3 years ago

Read 2 more answers

General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

3 years ago

USE THE INFORMATION AT

IceJOKER [234]

Answer:True

Step-by-step explanation:

6 0

3 years ago

6n-3>-18<br> Solve the inequality

Tamiku [17]

Answer:

Step-by-step explanation:

First, you have to isolate it on one side of the equation. Remember that, isolate n on one side of the equation.

6n-3>-18

6n-3+3>-18+3 (Add 3 from both sides.)

-18+3 (Solve.)

-18+3=-15

6n>-15

6n/6>-15/6 (Divide by 6 from both sides.)

-15/6 (Solve.)

-15/6=-5/2

n>-5/2

In conclusion, the correct answer is n>-5/2.

3 0

3 years ago