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shusha [124]
4 years ago
14

How long does it take to reach 1 million if you keep doubling a number everyday?

Mathematics
1 answer:
Darya [45]4 years ago
8 0
28 days or 672 hours
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A sampling of hemlock trees revealed that 7 out of 190 trees are infected with insects. About how many of the 950 hemlock trees
nignag [31]

Answer:

About 35 trees in a state park are infected with insects

Step-by-step explanation:

we know that

7 out of 190 trees are infected with insects

so

using proportion

Find out about how many of the 950 hemlock trees in a state park are infected with insects

\frac{190}{7}=\frac{950}{x} \\\\x=7(950)/190\\\\x= 35

therefore

About 35 trees in a state park are infected with insects

3 0
3 years ago
Work out whats 2f-4g
choli [55]

Step-by-step explanation:

I hope this helps. good luck

8 0
3 years ago
If a polygon is a square, then it is also a rectangle.<br><br><br> True<br><br> or <br><br> False
Art [367]

Answer:

true

Step-by-step explanation:

a square will always be a rectangle but a rectangle will not always be a square.

7 0
4 years ago
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HELP. How do i convert $1.34 into a percent %
Lelechka [254]
Ok. So, say you have 1 whole. If you take half of that it would be 50% or 0.50 of the whole. So with 1.34 you can turn it into 1 and 0.34. You have one whole, so that is 100 percent. You than add the 34 hundredths which is 34 percent. So you have 134%. Do you understand all that?
7 0
3 years ago
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P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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