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SVETLANKA909090 [29]

3 years ago

12

Math question help, please answer. ty xoxo will reward

1 answer:

SIZIF [17.4K]3 years ago

6 0

Slope formula: m = $\frac{(y2 - y1)}{(x2 - x1)}$

<em>Slope of segment BC:</em>

First, we substitute B (5, 2) for (x₁, y₁) and C (11, -6) for (x₂, y₂)

m BC = $\frac{(-6 - 2)}{(11 - 5)}$ = $\frac{-8}{6} = -\frac{4}{3}$

Slope of BC = A. $-\frac{4}{3}$

<em>Slope of segment AB:</em>

We substitute A (-3, -4) for (x₁, y₁) and B (5, 2) for (x₂, y₂)

m AB = $\frac{(2 - (-4))}{(5 - (-3))} = \frac{(2 + 4)}{(5 + 3)} = \frac{6}{8} = \frac{3}{4}$

Slope of AB = C. $\frac{3}{4}$

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Two hikers are 22 miles apart and walking toward each other. They meet in 5 hours. Find the rate of each hiker if one hiker walk

Irina-Kira [14]

Answer:

The hikers A and B travel at rates of 1.1 miles per hour and 3.3 miles per hour, respectively.

Step-by-step explanation:

Let suppose that each hiker travels at constant speed, such that kinematic formulas are, respectively:

Hiker A

$x_{A} = x_{A,o}+v_{A}\cdot t$

Hiker B

$x_{B} = x_{B,o} +v_{B}\cdot t$

Relationship

$v_{A} =- v_{B}-2.2\,mph$ (They walk toward each other)

Where:

$x_{A,o}$ , $x_{A}$ - Initial and final position of the hiker A, measured in miles.

$x_{B,o}$ , $x_{B}$ - Initial and final position of the hiker B, measured in miles.

$t$ - Time, measured in hours.

$v_{A}$ , $v_{B}$ - Velocities of hikers A and B, measured in miles per hour.

Given that $x_{A,o} = 0\,mi$ , $x_{B,o} = 22\,mi$ , $x_{A} = x_{B}$ and $t = 5\,h$ , the system of equation is reduced to the following:

$0\,mi -(v_{B}+2.2\,mph)\cdot (5\,h) = 22\,mi+v_{B}\cdot (5\,h)$

$-5\cdot v_{B}-11 = 22+5\cdot v_{B}$

$10\cdot v_{B} = -33$

$v_{B} = -3.3\,mph$

Now, the velocity of the hiker A is:

$v_{A} = - (-3.3\,mph)-2.2\,mph$

$v_{A} = 1.1\,mph$

The hikers A and B travel at rates of 1.1 miles per hour and 3.3 miles per hour, respectively.

6 0

3 years ago