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balu736 [363]
2 years ago
8

Is 27/51 equal to 18/34

Mathematics
2 answers:
marissa [1.9K]2 years ago
8 0
Yes, and first of all, you have already asked this question and secondly, yes it is equal to 18/34. Your solution is provided below. (It might not show up but you'll get what I mean)
27/51=18/34 Equation is alway trueRearrange:<span>Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     27/51-(18/34)=0 </span>Step by step solution :Step  1  : 9 9 Simplify —— - —— 17 17 Adding fractions which have a common denominator :<span><span> 1.1 </span>      Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:</span> 9 - (9) 0 ——————— = —— 17 17 <span>Equation at the end of step  1  :</span> 0 = 0 Step  2  :Solve 0 = 0 Equations which are always true :<span><span> 2.1 </span>   Solve   0  = 0This equation is a <span>tautology </span>(Something which is always true)</span>Equation is always true<span>
</span>
Nata [24]2 years ago
7 0
Yes.
27/51-18/34=0
if something minus something is zero, then the 2 numbers subtracting each other are equal. :)
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Simplify (5^-2)^4. Plsss help
Oksana_A [137]

Answer:

1/5^8

Step-by-step explanation:

We know that a^b^c = a^(b*c)

(5^-2)^4

5^(2*-4)

5^-8

We know that a^-b = 1/a^b

1/5^8

7 0
2 years ago
A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar
zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a Pr = \frac{2}{110}

b Pr = \frac{72}{110}

Step-by-step explanation:

Given

n = 11 --- hammers

r = 2 --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

Pr = P(D) * P(D)

Pr = \frac{2}{11} * \frac{2-1}{11-1}

Pr = \frac{2}{11} * \frac{1}{10}

Pr = \frac{2}{110}

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

P(D') = \frac{9}{11}

For two selections, the probability that all are not defective is:

Pr = P(D') * P(D')

Pr = \frac{9}{11} * \frac{9-1}{11-1}

Pr = \frac{9}{11} * \frac{8}{10}

Pr = \frac{72}{110}

8 0
2 years ago
Rob and Alan went to taco express. Rob bought seven tacos and to fajitas and paid $12.65. Adam bought 4 tacos and one fajita and
Nataliya [291]
I did the math and each taco is $1.25 each.
8 0
3 years ago
-2-5(4n-6)=-132 not really sure how to do this one ..
uranmaximum [27]

All you have to do is follow PEMDAS (if you don't know what that is, search it up).


-2-5(4n-6)=-132

Distribute the 5 to everything in the parentheses.

-2-20n+30= -132

Combine like terms.

-20n+28 = -132

Subtract 28 from both sides.

-20n = -160

Divide by -20 on both sides.

n = 8

8 0
2 years ago
Read 2 more answers
What is 3,333,333 rounded tp
Luba_88 [7]
To the nearest tenth: 3,333,330

To the nearest hundred: 3,333,300

To the nearest thousand: 3,333,000

To the nearest ten thousand: 3,330,000

To the nearest hundred thousand: 3,300,000

To the nearest million: 3,000,000

Hope that helps :)
5 0
3 years ago
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