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yanalaym [24]
3 years ago
5

Question/screenshot Below

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0
The answer is 10^8 for the question
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Out of the total respondents, the percentage of respondents from the 46–55 age group who rated the film excellent is %. write yo
Mrrafil [7]

Missing data:

Viewer's Age Group  Excellent Good Average Poor Marginal Total

16–25                          52                 42       12       7           113

26–35                          33                50         5       9          97

36–45                          58                 12       28      34         132

46–55                          25                17       22       12            76

56 +                               12                 5          3         8             28

Marginal Total             180               126      70      70           446

A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.

<h3>How to determine the rating of the film from the 46–55 age group?</h3>

A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.

25/446 = 0.05605

0.05605 * 100% = 5.605%

Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.

To learn more about data refer to:

brainly.com/question/4219149

#SPJ4

3 0
2 years ago
Solve the equation below for c.
tiny-mole [99]

Answer  c = (a-b)/d

Step-by-step explanation:

subtract b and divide by d

8 0
3 years ago
Evaluate the mean of each data set mentally.<br> 61, 71, 81, 91, 101
goldfiish [28.3K]

Answer:

10

Step-by-step explanation:

they each go by ten

4 0
3 years ago
Original price: $66; Markup: 20% The retail price is ?
andrezito [222]

Answer:

$79.20

Step-by-step explanation:

20% of $66 = $13.20

$66 + $13.20 = $79.20

4 0
3 years ago
Read 2 more answers
A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
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