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likoan [24]
3 years ago
6

I Need Help With This Math Question badly

Mathematics
1 answer:
posledela3 years ago
4 0

Answer:

3^{\frac{1}{6} }

Step-by-step explanation:

Using the rules of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

(a^m)^{n} = a^{mn}

Evaluating the parenthesis, gives

\frac{3^{\frac{3}{4} } }{3^{\frac{3}{8} } } = 3^{\frac{3}{4}-\frac{3}{8}  } = 3^{\frac{3}{8} } , then

(3^{\frac{3}{8})^{\frac{4}{9} }  } → \frac{3}{8} × \frac{4}{9} = \frac{1}{6}

= 3^{\frac{1}{6} } with x = \frac{1}{6}

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