Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:48 16 = ?
27 9 = 9
60 20 - 10
Step-by-step explanation:
<span>A) y = 3x because the slope (rate of change) is 3. The y-intercept is 0 so we don't necessarily need to add anything else.
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Answer:108
Step-by-step explanation: divided 81 and 3. the answer is 27. multiply 27 x 4 you get 108.
Answer:
-10
Step-by-step explanation:
-(x-5) ^2+25
-x+5^2+25
-5 -5
-x^2+20
-2x+20
---- ----
-2 -2
x=-10
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