Yes
⭐ Answered by Foxzy0⭐
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<h2>
Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>
Step-by-step explanation:
Let the number of milk chocolates be
.
Let the number of dark chocolates be
.
Given that the box contains the milk and dark chocolates in the ratio
.
So,
...(i)
Given that the total number of chocolates are
.
So,
. ...(ii)
Using (i) and (ii),
![m+\frac{4}{3}m=42](https://tex.z-dn.net/?f=m%2B%5Cfrac%7B4%7D%7B3%7Dm%3D42)
![\frac{7}{3}m=42](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B3%7Dm%3D42)
![m=18](https://tex.z-dn.net/?f=m%3D18)
![d=\frac{4}{3}m=\frac{4}{3}\times 18=24](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B4%7D%7B3%7Dm%3D%5Cfrac%7B4%7D%7B3%7D%5Ctimes%2018%3D24)
So,the number of milk chocolates are
and the number of dark chocolates are
.
Since the shape is a square the sides are equal. Then we need to find x such that x * x = 169.
Sqrt(169) = 13
So x = 13
Answer:
3x – 2 = 76 (Alternate Interior Angles)
3x = 76 + 2
3x = 78
x= 26°.
x + 2 = 40 (Alternate Interior angles).
x = 40 - 2
x= 38
<span>Using: a^2 + b^2 = c^2 (pythagoras theorem)
where 'a' and 'b' are the legs of a right triangle, c is the hypotenuse
</span><span>compare the triangle I just drew to the triangle you have for your problem
</span><span>you'll see that a = unknown b = 18 c = 36
</span><span>a=18sqrt3
=31.2</span>