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Answer is option C.
As given, alloy contains nickel = 14.25%
Weight of alloy = 375 pounds
Amount of nickel present in the alloy =
= 53.437 pounds
Rounding it we get option C = 53.44 pounds
L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
we got
a=1
b=6
c=-50
W=
W=
W=
W=
W=
W=
or W=
aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
we got
a=1
b=6
c=-50
W=
W=
W=
W=
W=
W=
aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59