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Sveta_85 [38]
3 years ago
14

The probability of event ???? is P(????)=0.5 , and the probability of event ???? is P(????)=0.7 . Are ???? and ???? disjoint? no

yes It is impossible to determine from the information given.
Mathematics
1 answer:
ki77a [65]3 years ago
3 0

Answer:

A and B are not disjoint.

Step-by-step explanation:

Given that there are two events A and B with prob

P(A)=0.5,

P(B)=0.7

If A and B are disjoint, there should not be any common element between A and B

P(AB) should be 0

But here we find P(A) + P(B) = 1.2>1

Since total probability is 1, there must be 0.2 atleast in P(AB)

which implies A and B cannot be disjoint.

A and B are not disjoint.

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Natali5045456 [20]

Answer:

Where's the question?

Step-by-step explanation:

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3 years ago
Two more than the product of a number and 8 is 5
Andreyy89
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Next it say two more which means adding so now we have, +2=5

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Rina8888 [55]
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4 years ago
Read 2 more answers
Riley is packing 144 pencils, 120 files, and 108 notebooks into as many boxes as possible. Find the greatest number of boxes tha
Vaselesa [24]

Answer:

<em>Greatest number of boxes to pack all items into them equally will be 12 where each box contain 10,12,9 files, notebooks and pencils respectively.</em>

Step-by-step explanation:

To find the greatest number of boxes that Riley could pack the items into, we have to find the HCF of 144, 120 and 108.

We will find the HCF through prime factorization.

<em>("Prime Factorization" is finding which prime numbers multiply together to make the original number)</em>

<u>Step 1:</u>

Find the prime factorization of each of the given numbers.

<u>Step 2:</u>

The product of all common prime factors is the HCF of the given numbers.

First number is 120:

120 = 2*2*2*3*5

Second number is 144:

144 = 2*2*2*2*3*3

And last number is 108:

108 = 2*2*3*3*3

Now we will match the numbers which are common in all three values. In other words we will find the common factors.

<em>The common factors in 120,108 and 144 are:</em>

<em>2*2*3</em>

If we multiply 2*2*3 we get 12

Hence, HCF of ( 120,108,144 ) = 12

<em>Therefore, Greatest number of boxes to pack all items into them equally will be 12 where each box contain 10,12,9 files, notebooks and pencils respectively.</em>

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