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Vanyuwa [196]
3 years ago
12

What is the answer?​

Mathematics
1 answer:
alex41 [277]3 years ago
4 0

Answer/Step-by-step explanation:

Given:

Data set for sandwich calories=> 242, 290, 290, 280, 390, 350

Mean: the mean is given as sum of all values in the data set ÷ total no. of data set given

\frac{242 + 290 + 290 + 280 + 390 + 350}{6} = \frac{1,842}{6} = 307

Mean Absolute Value:

Step 1: find the absolute value of the difference between each value and the mean

|242 - 307| = 65

|290 - 307| = 17

|290 - 307| = 17

|280 - 307| = 27

|390 - 307| = 83

|350 - 307| = 43

Step 2: find the sum of all values gotten in step 1

65 + 17 + 17 + 27 + 83 + 43 = 252

Step 3: divide the result you get in step 2 by 6 to get the M.A.D

M.A.D = \frac{252}{6} = 42

The Mean Absolute Value represents or gives us an idea how spread the data set for the number of sandwich calories are.

Thus, averagely, the number of calories of sandwich at the restaurant are far from the mean caloric value by 42 calories.

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What is the correct first step to solve this system of equations by elimination?
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\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

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