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pashok25 [27]
2 years ago
14

According to the histogram, how many shipments had more than 20 light bulbs broken? A) 4 B) 6 C) 7 D) 12

Mathematics
1 answer:
bearhunter [10]2 years ago
6 0

The histogram depicts that the number shipments that had more than 20 light bulbs broken is D. 12.

<h3>What is a histogram?</h3>

A histogram simply means a graphical representation that is used to organize a group of data points into ranges.

From the complete question, the histogram shows that the number shipments that had more than 20 light bulbs broken is 12. This can be interpreted based on the ranges shown in the histogram.

Learn more about histogram on:

brainly.com/question/1581651

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Bitsy Betsy is only 4 and half feet tall. How many inches is she?
max2010maxim [7]

Answer:

54 inches

Step-by-step explanation:

first you're going to want to put four and a half feet into a decimal (4.5) and multiply it by how many inches are in 1 ft ( 12). after that you're going to want to count how many decimal paces there are (2) and move your decimal at the end of 5400 to 54.00. The extra 0s are not needed.

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Need help i dont understand this.
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The range is a statistical property that consists of the difference between the biggest and the smallest given number.

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6 0
3 years ago
Three times one number added to five times another number is 54. The second number is two less than the first. Use a system of e
worty [1.4K]

Answer:

8 and 6

Step-by-step explanation:

If you use x for the first number, and y for the second, you get equations of 3x+5y=54 and x-2=y.

You can substitute the second equation into the first one to solve it. This gives 3x+5(x-2)=54.

The brackets can be expanded to 3x+5x-10=54. Collecting like terms makes it 8x-10=54.

Next, we add 10 to both sides. This gives 8x=64.

From there, we isolate the x by dividing both sides by 8, giving x=8.

To work out the second number, we can sub 8 for x in either equation (I'm using the second one as it's simpler).

This comes to y=8-2, therefore y=6.

**This content is simultaneous equations, which you may wish to revise. I'm always happy to help!

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3 years ago
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