Answer:
Yes, they only need 400 tickets to meet their goal, any more will exceed their goal.
Step-by-step explanation:
Answer:
The complement of the given set in interval notation is
. It can we written as (-inf,5]U(6,inf).
Step-by-step explanation:
The given set in interval notation is
(−5,6]
It means the set is defined as

If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.
Here, universal set is R, the set set of all real numbers.

The complement of the given set is


Complement of the given set in interval notation is
![A^c=(-\infty,-5]\cup(6,\infty)](https://tex.z-dn.net/?f=A%5Ec%3D%28-%5Cinfty%2C-5%5D%5Ccup%286%2C%5Cinfty%29)
Therefore the complement of the given set in interval notation is
. It can we written as (-inf,5]U(6,inf).
Answer:
(-1, -3)
Step-by-step explanation:
We suppose your notation means you want to reflect given point P across the horizontal line y=1.
The x-coordinate will remain the same.
The new y-coordinate will be such that y=1 is the midpoint between the original and its reflection:
(5 + y)/2 = 1
5 + y = 2 . . . . multiply by 2
y = 2 -5 = -3 . . . subtract 5
The reflected point is (-1, -3).
___
The same sort of math applies whenever you have a midpoint and want to find the other end point. Double the midpoint value and subtract the end point you have in order to find the other end point.
<h3>The answer to your question is k (-3) = 21!</h3>
Here's how I got this answer:
<em><u>K(a) = 2a^2 - a </u></em>
<em><u>K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)</u></em>
<em><u>K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3</u></em>
<em><u>K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3K (-3) = 18 + 3</u></em>
<em><u>K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3K (-3) = 18 + 3K (-3) = 21</u></em>
I hope this helps!
Also sorry for the late answer, I just got the notification that you replied to my comment, I hope I came in time!