All categories

3 years ago

Can some one answer 7 and more if you want to

Mathematics

1 answer:

QveST [7]3 years ago

4 0

A) 3x8=24 (so the value of n is 8)
B) 5x12=60
C) 12x12=144
D) 160=8x20
E) 2x3x3x3=54

You might be interested in

A contractor charges $35 for the installation of gutters, plus $1.50 per foot. If one installation cost $162.50, how many feet o

guajiro [1.7K]

162.50-35.00=127.50
127.50/12=10.63
10.63 feet of guttering were required

7 0

3 years ago

Help answer for a b and c work all of it out and show your work!thanks. Use the picture.

frozen [14]

216.4 is the total cost added up.

198.77 would be the subtraction of the answer above with the hardware supplies but subtraction would be wrong so you'd have to divide, dividing would get you to 0.0814, the you'll have to divide the decimal by 100 giving you 0.0815.

Do the same steps above but with the paint and hardware.

52.91/216.4 gives you 0.244501, rounded up would give you 0.000245.

Add those two totals together to get your answer, 0.081745.

Sorry if I'm wrong. Hope this helps!

4 0

3 years ago

On April 11, 2012, two earthquakes were measured off the northwest coast of Sumatra. The first had a magnitude of 8.6. The secon

Hoochie [10]

Answer:

Option D. 2.51 is correct.

Step-by-step explanation:

Magnitude of first earthquake = 8.6

Let intensity of first earthquake be x

$Magnitude = \log(\frac{x}{S}),\text{ where S is seismographic factor}\\\\\implies 8.6=\log(\frac{x}{S}).......(1)$

Magnitude of second earthquake = 8.2

Let intensity of second earthquake be y

$Magnitude = \log(\frac{y}{S}),\text{ where S is seismographic factor}\\\\\implies 8.2=\log(\frac{y}{S}).......(2)$

Now, to find the factor by which intensity of first earthquake is greater than intensity of second : we divide equation (1) by equation (2)

$\implies\log(\frac{x}{y})=8.6 - 8.2\\\\\implies \log(\frac{x}{y})=0.4\\\\\implies\frac{x}{y}=10^{0.4}\\\\\implies\frac{x}{y}=2.51$

Hence the required factor is 2.51

Therefore, Option D. 2.51 is correct.

4 0

3 years ago

Precal help if you could could you answer both. Me finishing this helps me graduate.

oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

$z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))$

In this form, you have

$z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))$

The magnitude of the number is given by

$z=a+bi \implies \rho = \sqrt{a^2+b^2}$

So, we have

$z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2$

As for the angle, we have

$z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}$

So, we have

$z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}$

Finally,

$z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64$