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3 years ago

Solve by factoring: 8p2 - 64p = 0

1 answer:

3 0

You begin with moving all terms to the left side and set them equal to zero. Then you set each factor equal to zero and you should come out with p= 0,8

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A farmer buys a horse for $60. He sells it to his neighbor for $70. Then he discovers he could have made a better deal. He borro

Ne4ueva [31]

He only made $10. Considering the horse was sold for $90.

4 0

3 years ago

Read 2 more answers

geniusboy [140]

a= $\pi$ $r^{2}$

The area of a pizza with a diameter of 10 inches is 78.5.

8 0

3 years ago

Factorise the following expression using grouping and use binomial products to simplify.

rewona [7]

Answer:

11x-55-5a+ax

11(x-5)+a(x-5)

(11+a)(x-5)

Step-by-step explanation:

First you factor out the common factors

for(11x-55) is would be 11 as both of these figures are the multiple of 11

for(ax-5a) the common factor is a which will be factor out

Then after doing the process you will get

11(x-5)+a(x-5)

then factor out(x-5)which will give you

(11+a)(x-5)

6 0

4 years ago

Read 2 more answers

Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

lubasha [3.4K]

Answer in order:

False

True

False

True

Step-by-step explanation:

All of the solutions to the equation $3x^2 - 12 = 0$ are x = 12 and x = -12

Solve:

Common factor - $3(x^2-4)=0$

Divide both sides

$x^2-4=0$

Use the quadratic formula

$x=\sqrt{4,x}=\sqrt{-4$

x = 2, x = -2

Thus, This is false..

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There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

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The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

$2x^3-18x^2+54x-72=0$

$x=5.080084$

Hence this is false

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The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

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The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

$(x+3)^2=17$

$x=\sqrt{17-3,}=-\sqrt{17}-3$

Hence this is false.

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The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

$(2x-1)^2=9$

x=2, x = -1

Hence this is false.

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The only solution for equation (2x-1)^2-49=0 is x = 4

$(2x-1)^2=49$

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

$3(x+2)^2=3$

$(x+2)^2=1$

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x = -6

Add 180 to both sides

$5x^2-180+180=0+180$

$5x^2 = 180$

$x^2 = 36$

$x=\sqrt{36},x=-\sqrt{36}$

x = 6, x = -6

Hence, this is true.

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[RevyBreeze]

7 0

3 years ago

A person invests 3000 dollars in a bank. The bank pays 6.75% interest compounded

stich3 [128]

Answer:

12.1 years

Step-by-step explanation:

We are given that

Principal amount, P=$3000

Rate of interest, r=6.75% semi-annually

Amount, A=$6700

We know that

When r pays semi-annually

$A=P(1+\frac{r}{n\times 100})^{nt}$

Where n=2

Using the formula

$6700=3000(1+\frac{6.75}{200})^{2t}$

$\frac{6700}{3000}=(1..03375)^{2t}$

$2.233=(1.03375)^{2t}$

Taking ln on both sides we get

$ln(2.233)=2t ln(1.03375)$

$2t=\frac{ln(2.233)}{ln(1.03375)}$

$t=\frac{1}{2}\times \frac{ln(2.233)}{ln(1.03375)}$

$t=12.1 years$

8 0

3 years ago