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Basile [38]
3 years ago
13

Simplify: (3x2 − 8xy + y2) − (7x2 − 4xy − 5y2)

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0

Answer:

-4xy - 8x + 12y

Katena32 [7]3 years ago
6 0

Answer:

-4x^{2} -4xy+6y^{2}

Step-by-step explanation:

(3x2 − 8xy + y2) − (7x2 − 4xy − 5y2)

First, we remove the parenthesses. We can just remove the first parnthesses because there isn't any sign before them. When removing the second ones, we will change the sign of every term in it. It becomes:

3x^{2} -8xy+y^{2} -7x^{2} +4xy+5y^{2}

Now we will combine the like terms. That means that we will subtract 7x2 from 3x2, add 4x to -8x etc.

-4x^{2} -4xy+6y^{2}

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Write the equation of the line that passes through the points (−4,1) and (−9,5). Put your answer in fully reduced point-slope fo
valina [46]

Step-by-step explanation:

gradient(m)=change in y/change in x

=5-1/-9-(-4)

=4/-9+4

=4/-5

equation now

y-y1=m(x-x1)

y-1=4/-5[x-(-4)]

y=4/-5(x+4)+1

y=-4/5x-16/5+1

y=-4/5x-21/5

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Answer:

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Step-by-step explanation:

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3 years ago
Renaldo catches the bus at 4:00 onto ride 3.2 miles from his house to the dentist office. He arrives at 4:30 p.m for one hour ap
asambeis [7]
The bus is traveling at 6.4 miles per hour. The appointment was 1 hour long so he gets out at 5:30. From 5:30 to 6:30 is one hour, and at that speed, the bus could go 6.4 miles within that timeframe. So yes, he has time because 6.4 is greater than 4.8.
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4 years ago
[(23 × 2.5) , 1 2] + 120<br> Please solve
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John was visiting four cities that form a rectangle on a coordinate grid at A(0, 4), B(4, 2), C(1, -4) and D(-3, -2). What is th
allsm [11]

Answer:

Area = 30

Step-by-step explanation:

Given

Rectangle coordinates

A = (0,4)

B = (4,2)

C = (1,-4)

D =(-3,-2)

Required

The area of the rectangle

The area is calculated as:

Area = Length* Width

The length of the rectangle will be represented as:

Length = AB = CD

And the width is:

Width = BC = AD

Calculate distance AB using:

AB = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }

Where:

A = (0,4) --- (x_1,y_1)

B = (4,2) --- (x_2,y_2)

AB = \sqrt{(0 - 4)^2 +(4 - 2)^2 }

AB = \sqrt{(- 4)^2 +(2)^2 }

AB = \sqrt{16 +4 }

AB = \sqrt{20}

Calculate distance BC using:

BC = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }

C = (1,-4) ---(x_1,y_1)

B = (4,2) --- (x_2,y_2)

BC = \sqrt{(1 - 4)^2 +(-4 - 2)^2 }

BC = \sqrt{(- 3)^2 +(-6)^2 }

BC = \sqrt{9 +36}

BC = \sqrt{45}

So, the area is:

Area = Length * Width

Area = AB * BC

Area = \sqrt{20} * \sqrt{45}

Area = \sqrt{20 * 45}

Area = \sqrt{900

Area = 30

4 0
3 years ago
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