The function has neither because it goes infinitely up and infinitely down
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
P-Q should be -11a^2+4b^2+ab
Answer:
Step-by-step explanation:
<h2><u>Part A</u></h2>
in interval ( 0 ; 2)
<h2><u>Part B</u></h2>
in interval (2; 4)
<h2><u>Part C</u></h2>
in interval (4 ; 6 )
<h2><u>Part D</u></h2>
The graph shows that at first the ball rises up ; and then it is seen that it goes down and loses height to zero , from which it can be concluded that the height after 10 seconds remains unchanged and therefore the height of the ball after 16 seconds will be zero
<span>from the whole price,
15% of this price is equal to $18.00.
therefore if 15 % equals $18.00
then 100% is the original price therefore 100 % = 18.00 / 15 % x 100% = $120 therefore original price = $120</span>
