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spin [16.1K]
3 years ago
7

Jada, Lin, and Elena are saving money for a trip. Together they saved $120. Jada saved $20 less than Lin. Lin saved 3 times as m

uch money as Elena. How much money did each of them save?
Mathematics
1 answer:
defon3 years ago
6 0

Step-by-step explanation:

This is a word problem that we must translate to mathematical expression before we can solve.

let the individual saving be the first letters of the names

Jada= J

Lin= L

Elena= E

1. Jada saved $20 less than Lin

    J=L-20

2. Lin saved 3 times as much money as Elena

   L= 3E

3. Hence Elena saved

   E

Together they saved $120.

hence

(L-20)+3E+E= 120

L-20+3E+E= 120

collecting like terms we hav

L+4E=120+20

L+4E= 140

but we know that L= 3E

3E+4E= 140

7E= 140

divide both sides by 7 we have

E= 140/7

E= $20

This means Elena saves $70

also  L= 3E

L= 3*20

L= $60

this means that Lean saved $60

also  J=L-20

J= 60-20

J= $40

This means that Jada saved $40

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Shawna found coins worth $4.32. One- fourth of the found coins are pennies and one- sixth are quarters. The number of nickels fo
eduard

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

The trick is to ASSUME the dimes.

Start by thinking about the three explicit premises and the one implicit premise.

1) Quarters = 1/6 of total coins

2) Nickels = 1.5 the number of quarters

3) Pennies = 1/4 of total coins

Also, ASSUME an unknown number of dimes to fill in the gap.

48 Total Coins = $4.32

⅙ of 48 = 8 8 quarters = $2.00

1.5 x 8 = 12 12 nickels = $0.60

¼ of 48 = 12 12 pennies = $0.12

Add those coins = $2.72

Take the known total and minus this sum.

$4.32 - $2.72 = $1.60

16 dimes = $1.60

Thus, you have the following:

8 quarters (⅙ of total coins)   $2.00

12 nickels (1.5 the number of quarters) $0.60

12 pennies (¼ the number of total coins) $0.12    

+ 16 dimes     $1.60

Total Coins 48      $4.32

8 0
3 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

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\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

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\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

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\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

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3 0
2 years ago
B
Tom [10]

Answer:

(a) 320 cm²

(b) 75 cm³

Step-by-step explanation:

The scale factor from A to B is 8/4 = 2.

The scale factor of the areas is 2² = 4.

The scale factor of the volumes is 2³ = 8.

(a)

80 cm² * 4 = 320 cm²

(b)

600 cm / 8 = 75 cm³

8 0
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Answer:

$15.44

Step-by-step explanation:

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