The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
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Answer:
$26.87
Step-by-step explanation:
if the shirt was 35% off, then you paid 65% of the cost
that value can be found by:
39 x .65 = 25.35 (this is the amount paid for the shirt)
sales tax of 6% on 25.35 is:
.06 x 25.35 which equals 1.52
25.35 + 1.52 = 26.87
The munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
<h3>
What are nonnegative real numbers?</h3>
- Non-negative real numbers are the set of positive real numbers that are bigger than 0 (zero).
- That is, the true values are either positive or negative.
- The collection will include numbers such as 0, 1, 2, 3, 4, 5, and so on.
To find the minimum value of 10x (3y/5):
Given - y = 3/(2x)
So, we want the bare minimum of,
- = 10x + 3/5 × 3/(2x)
- = 10x + 9/(10x)
Take the derivative to obtain:
When you set it to zero, you get:
- = 100x^2 - 9 = 0
- = (10x-3)(10x+3) = 0
- = x = ± 3/10
So, at x = 3/10, y = 5 and 10x + 3y/5 = 3 + 3 = 6.
Therefore, the munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
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6k + 33 = 20 - 10k
16k = -13
K= -1.2307
