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Bingel [31]
4 years ago
5

A cylindrical swimming pool has a diameter of 16 feet and a height of 4 feet. About how many gallons of water can the pool conta

in? Round your answer to the nearest whole number. (1 ft³ ≈ 7.5 gal)
To the nearest whole number, the pool can hold ______ gallons of water.
Mathematics
1 answer:
xenn [34]4 years ago
8 0

Answer: 6029 gal

Step-by-step explanation:

The volume of cylinder is given by :-

\text{Volume}=\pi r^2h

Given : Diameter of cylindrical pool = 16 feet

Radius of cylindrical pool =\frac{16}{2}=8\ ft

Height of cylindrical pool = 4 feet

Now, The volume of cylindrical pool is given by :-

\text{Volume}=\pi (8)^2(4)\\\\\Rightarrow\ \text{Volume}=3.14(64)(4)\\\Rightarrow\ \text{Volume}=803.84\ ft^3

It is given that 1\ ft^3=7.5\ gal

Therefore, The amount of water can the pool contain = 7.5\times803.84\ gal=6028.8\ gal\approx6029\ gal

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Vesnalui [34]
Consider the figure attached.

Let m(R)=α degrees and m(T)=β degrees.

1.
Angle R, is an inscribed angle, intercepting the arc WTS. 
This means that the measure of the arc WTS is double the measure of the angle R,

so m(arc WTS) = 2α degrees.

2.
Similarly, 

Angle T, is an inscribed angle, intercepting the arc WRS. So 

m(arc WRS) = 2β degrees.

3.
m(arc WTS)+m(arc WRS)=360° since these arcs cover the whole circle.

thus 

2α+2β=360°

divide by 2:

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this means T and R are supplementary angles. 

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3 years ago
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Ulleksa [173]

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If they are similar, and the second cube's length is 3 times that of the first, then all of the sides are 3 times as large. 
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Hope I helped! xx
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