Quadrilateral STWR is inscribed inside a circle as shown below. Write a proof showing that angles T and R are supplementary. Cir
cle Q is shown with an inscribed quadrilateral labeled RSTW.
1 answer:
Consider the figure attached.
Let m(R)=α degrees and m(T)=β degrees.
1.
Angle R, is an inscribed angle, intercepting the arc WTS.
This means that the measure of the arc WTS is double the measure of the angle R,
so m(arc WTS) = 2α degrees.
2.
Similarly,
Angle T, is an inscribed angle, intercepting the arc WRS. So
m(arc WRS) = 2β degrees.
3.
m(arc WTS)+m(arc WRS)=360° since these arcs cover the whole circle.
thus
2α+2β=360°
divide by 2:
α+β=180°
this means T and R are supplementary angles.
Let m(R)=α degrees and m(T)=β degrees.
1.
Angle R, is an inscribed angle, intercepting the arc WTS.
This means that the measure of the arc WTS is double the measure of the angle R,
so m(arc WTS) = 2α degrees.
2.
Similarly,
Angle T, is an inscribed angle, intercepting the arc WRS. So
m(arc WRS) = 2β degrees.
3.
m(arc WTS)+m(arc WRS)=360° since these arcs cover the whole circle.
thus
2α+2β=360°
divide by 2:
α+β=180°
this means T and R are supplementary angles.
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<u>Given</u>:
Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.
The marbles are selected by not replacing the drawn ones.
We need to the probability of selected a black marble and then a white marble without replacement.
<u>Probability</u>:
Let B denote the black marble.
Let W denote the white marble.
The probability of selecting a black marble is
The probability of selecting a white marble without replacement is
The probability of selecting a black marble and then a white marble without replacement is given by
Substituting the values, we get;
Thus, the probability of selecting a black marble and then a white marble without replacement is