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3 years ago

Write an inequality and solve each problem.

1 answer:

6 0

The unknown number equals x. (you can use any other letter)
the unknown number is being subtracted by 3.
x-3.
now if it is no more than 2, it must be less than 2,
x-3<2
hope this helps

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A bike wheel is 26 inches in diameter. What is the bike wheel's diameter in millimeters (1 inch = 25.4 millimeters)?

Alex

Given that, a bike wheel is 26 inches in diameter.

We need to convert bike wheel's diameter in millimeters .

Since, 1 inch = 25.4 millimeters.

So, to convert 26 into mm we need to multiply 26 each sides of this identity to convert this into mm. Hence,

1*26 inch = 25.4 * 26 mm.

So, 26 inches = 660.4 mm.

So, the bike wheel's diameter is 660.4 millimeters.

Hope this helps you!

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3 years ago

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What is 2466 divided by 3

Romashka-Z-Leto [24]

2466/3 is equal to 822.

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3 years ago

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Complete the table so that the cost per banana remains the same.

Aneli [31]

Step-by-step explanation:

No. of banana Cost Unit price

4 2 0.50

6 3 0.50

7 3.5 0.50

20 10 0.50

33 16.50 0.50

Cost = No of banana x unit price

Cost = 4 x 0.50 = 2

Cost = 6 x 0.50 = 3

Cost = 7 x 0.50 = 3.50

Cost = 20 x 0.50 = 10

No of banana = Cost / Unit price

No of banana = 10 / 0.50 = 20

No of banana = 16.50 / 0.50 = 33

3 0

3 years ago

What is 4.345 x 10^5 in standard form?

zalisa [80]

Answer:

Choice D.) 434,500

Step-by-step explanation:

What is 4.345 x 10^5 in standard form?

4.345 x 10^5 = 4.345 * 100,000

multiply it out:

4.345 x 10^5 = 434,500

3 0

3 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago