Question

Find the inverse of the one-to-one function f(x)=-8x+8

Answer 1

Answer:

$\huge\boxed{f^{-1}(x)=-\dfrac{1}{8}x+1}$

Step-by-step explanation:

$f(x)=-8x+8\to y=-8x+8$

change x with y

$x=-8y+8$

solve for y

$-8y+8=x$          subtract 8 from both sides

$-8y+8-8=x-8$

$-8y=x-8[\tex] divide both sides by (-8)[tex]\dfrac{-8y}{-8}=\dfrac{x}{-8}-\dfrac{8}{-8}\\\\y=-\dfrac{1}{8}x+1$