Answer:
First evaluate 4^t
put x= 1 in 4^x
It's 4^1 = 4 but f(x) = 8
So we need to multiply with 2
So it's A) 2.4^x
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
fjhdfdsfklsdfsfsdfdfdfsfs
Answer:
(3 , 2.5)
Step-by-step explanation:
.5x + y = 4
y = .5x+1
.5x + (.5x + 1) = 4
x + 1 = 4
x = 3
y = .5(3)+1
y = 1.5 + 1
y = 2.5
Answer:
the answers are all in the picture
Step-by-step explanation:
Lmk if you need more explaining :)
