All categories

3 years ago

HELP PLEASE...................................

Mathematics

2 answers:

Furkat [3]3 years ago

6 0

All you have to do is break this image into parts of two different shapes and find the areas of those two shapes. Then you can add them together and you will have your answer. Your work should look like this:

For one of the rectangles:

Length * Width

8 * 10 = 80

For the other rectangle:

Length times width

10 - 5 = 5 (You have to subtract 10 - 5 because you need to know the measurement of the of the width of the top rectangle, and the top rectangle is not a full 10 inches like the bottom one. )

15 - 8 = 7 (For the same reason as the width, you also need to subtract to find the length of the top rectangle.)

Now multiply.

Length * width

5 * 7 = 35

Now that you have the two areas of the two separate rectangles, you can add them together.

35 + 80 = 115

Keith_Richards [23]3 years ago

6 0

The answer is 115cm2

You might be interested in

Angles a and b are complementary angles symmetry of angle a is 28° more than the measure of angle b find the missing angle measu

scoray [572]

Answer:

31 , 59

Step-by-step explanation:

a = b +28

a + b = 90 {Complementary}

b + 28 + b = 90 {Combine like terms}

2b + 28 = 90 {Subtract 28 form both sides}

2b = 90 - 28

2b = 62 {Divide both sides by 2}

b = 62/2

b = 31

a = 31 + 28

a = 59

7 0

3 years ago

Divide: 16)160 A. 10 B. 11 C. 16 D. 26 E. 100

grin007 [14]

Answer:

Step-by-step explanation:

your welcome...............

3 0

3 years ago

A regular hexagon has sides of 3 feet. What is the area of the hexagon?

frosja888 [35]

Answer:

$13.5\sqrt{3}\:\text{ft}^{2}$

Step-by-step explanation:

Given: The side of a regular hexagon is 3 feet.

To find: Area of the hexagon

Solution:

It is given that the side of a regular hexagon is 3 feet.

We know that the area of a regular hexagon whose side is a units is $\frac{3\sqrt{3} }{2} a^{2}$

Here, the side is 3 feet

So, area of the regular hexagon

$=\frac{3\sqrt{3} }{2} \times3^{2}$

$=\frac{3\sqrt{3} }{2} \times9$

$=\frac{27\sqrt{3} }{2}$

$=13.5\sqrt{3}\:\text{ft}^{2}$

Hence, area of the regular hexagon is $13.5\sqrt{3}\:\text{ft}^{2}$

6 0

3 years ago

In 12 games last season the school baseball team scored 5, 11, 2, 0, 4, 8, 9, 6, 7, 4, 1, and 2 runs. What is the average number

Mashcka [7]

Hello there!

First, we need to put our data set into proper numerical order (least to greatest).

Set: , 1,2,2,4,4,5,6,7,8,9,11

Now, to find the mean, we need to add them all up.

1 + 2 + 2 + 4 + 4 + 5 + 6 + 7 + 8 + 9 + 11 = 59

Then, divide it by how many numbers there are : 12

59 divided by 12 = 4.9166667

Round it to the nearest tenth.

4.9166667 = 4.9

This means the average number of runs scored per game is 4.9 runs.

7 0

4 years ago

Hey can you please help me posted picture of question

Nady [450]

(8x^2+5x+3)+(-5x^6-2x^5+4x^2-2x)=
8x^2+5x+3-5x^6-2x^5+4x^2-2x=
-5x^6-2x^5+(8-4)x^2+(5-2)x+3=
-5x^6-2x^5+4x^2+3x+3

Answer: Option B. -5x^6-2x^5+4x^2+3x+3

3 0

3 years ago

Read 2 more answers