There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Answer:
6 slices
Step-by-step explanation:
The full pizza is 12 pieces. Divide 12 by 4 to find out how much she ate on Thursday. 1/4 of 12 is 3 so she ate 3 slices on Thursday. Subtract 3 from 12 to find out how much was left for the next day. There were 9 slices the next day. Next, divide 9 by 3 to find out what 1/3 of 9 is. 1/3 of 9 is 3 so subtract 3 from the 9 slices. 6 slices are the original pizza remain.
Answer:
Step-by-step explanation:
You can start by dividing both sides by 2, getting .
, or 1.75<u />