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3 years ago

I need help on number 16

Mathematics

1 answer:

ollegr [7]3 years ago

5 0

There will be two squares.

Think about it: The shorter side is 3.5 feet. The longer side is 7 feet. If he cuts it in half on the longer side, he's taking the length of that longer side, and dividing it by 2. 7/2=3.5.

So, you'd have two squares, both with a length and width of 3.5 feet.

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Classify the triangle by its sides, and then by its angles.

Gekata [30.6K]

Answer:

Equilateral, acute

Step-by-step explanation:

Equilateral triangles have all sides the same length (all sides are 4 ft in this triangle, so it is equilateral).

Acute triangles have no angles that are greater than or equal to 90 degrees (all angles are 60, which is less than 90, so it is acute).

3 0

3 years ago

Does (2, 8) make the equation y = 4x true?

guajiro [1.7K]

Answer:

Yes, it does.

Step-by-step explanation:

The equation y = 4x is the same as saying:

"The y coordinate is 4 times as much as the x coordinate"

So, with the coordinate set of (2, 8):

y = 4x

8 = 4 * 2

This is correct, meaning the coordinate does fit the equation.

Hope this helps!

6 0

2 years ago

Read 2 more answers

Please help. I don't understand this. Thanks.

neonofarm [45]

Yes;k=-3 and y=-3x is the answer because 2 x -3 = -6 -3 x -3 = -9 and etc..

4 0

3 years ago

What is the constant of proportionality of $18.36 for 2 pizzas

sergeinik [125]

Answer:

9.18

Step-by-step explanation:

7 0

3 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

3 years ago