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AlladinOne [14]
3 years ago
5

PLEASE HELP!!!!!!! Read the photo provided

Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

See below (and I will be using decimals)

Step-by-step explanation:

First, let's organize the numbers from least to greatest:

(2, 1.5, 1.25, 1.75, 1.5, 2, 1.75, 1.5, 2)

into

(1.25, 1.5, 1.5, 1.5, 1.75, 1.75, 2, 2, 2)

Now, let's input them into the table.

-. -. -. -. -.

-. -. -. -. -.

-. -. -. -. -.

-. -. X -. X

-. -. X X X

-. X X X X

1 1.25 1.5 1.75 2

The smallest amount of flour that the baker uses is 1.25 cups.

Hope this helps!

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Can someone please explain this question?
aksik [14]

Answer:

The limit does not exist

Step-by-step explanation:

lim as we approach from below 7

x+5 when x=7  

7+5

12

lim as we approach from above 7

5x-25 when x=7  

5*7 -25

35-25

10

The limit does not exist since these numbers are not the same

6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
Fed [463]

Answer:

b -17

Step-by-step explanation:

−a^2 − 3b^3 + c^2 + 2b^3 − c^2 =

= -(3²) - 3(2³) + (-3)² + 2(2³) - (-3)²

= -9 - 3(8) + 9 + 2(8) - 9

= -9 - 24 + 9 + 16 - 9

= -17

8 0
2 years ago
Find slope between (6, –2) and (8, –2)
lorasvet [3.4K]
0, the slope is 0. your y points are the same number so the slope is not going to be positive or negative.

7 0
3 years ago
Find the value of x for which p is parallel to q, if m∠1 = (9x) and m∠3 = 117 .The diagram is not to scale.
kherson [118]
Oh I see sorry . My bad thinking!

m< 1 = m<3 ( corresponding angles) so

9x = 117 
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x = 13 Answer
3 0
3 years ago
The areas of two similar triangles are 20m2 and 180m2. The length of one of the sides of the second triangle is 12m. What is the
guajiro [1.7K]

Answer:

The corresponding side of the first triangle is 4 m.

Step-by-step explanation:

Area of the first triangle: A1=20 m^2

Area of the second triangle: A2=180 m^2

Lenght of one of the sides of the second triangle: s2=12 m

Corresponding side of the first triangle: s1=?

A1/A2=(s1/s2)^2

Replacing the known values:

(20 m^2)/(180 m^2)=[s1/(12 m)]^2

Simplifying:

2/18=[s1/(12 m)]^2

Simplifying the fraction on the left side of the equation dividing the numerator and denominator by 2:

(2/2)/(18/2)=[s1/(12 m)]^2

1/9=[s1/(12 m)]^2

Solving for s1: Square root both sides of the equation:

sqrt(1/9)=sqrt{[s1/(12 m)]^2}

sqrt(1)/sqrt(9)=s1/(12 m)

1/3=s1/(12 m)

Multiplying both sides of the equation by 12 m:

(12 m)*(1/3)=(12 m)*s1/(12 m)

Simplifying:

(12 m)/3=s1

4 m=s1

s1=4 m

8 0
4 years ago
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