All categories

3 years ago

Can somebody help me please I need help

Mathematics

1 answer:

V125BC [204]3 years ago

7 0

What do you need help with?

You might be interested in

On a coordinate plane, a parabola opens up. It goes through (negative 8, negative 2), has a vertex at (negative 5, negative 6.5)

Nady [450]

Answer:

Step-by-step explanation:

<h2>Hope it helps</h2>

8 0

2 years ago

Which function is shown in the graph below?

Helga [31]

Answer:

Step-by-step explanation:

I’m not entirely sure if this is right but I hope I helped.

8 0

3 years ago

Hey guys this is really in hard what is 1-5=

Amiraneli [1.4K]

Answer:

-4

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

PLEASE HELP!!!! IMA DESPRATE!!!!!!!!Find the second term in the sequence defined by an = −5(n2 + 1n).

Dmitrij [34]

The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20

<h3>How to find the nth term of a sequence?</h3>

We are given the formula for a sequence as;

aₙ = -5(n² + 1n)

Where n is the position of the term.

Now, for the first term, we will have;

a₁ = -5(1² + 1(1))

a₁ = -10

The second term of the sequence is;

a₂ = -5(2² + 1(2))

a₂ = -20

Read more about Sequence at; brainly.com/question/6561461

#SPJ1

5 0

2 years ago

Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples

zheka24 [161]

Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25

Step-by-step explanation:

melanin content Total

high low

moisture high 13 10 23

content low 47 30 77

Total 60 40 <u> </u><u>100</u>

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)= $\dfrac{40}{100}=0.40$

b) Total skin samples has high moisture content = 13+10=23

P(B) = $\dfrac{23}{100}=0.23$

c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) = $\dfrac{10}{100}=0.10$

Using conditional probability formula , $P (A|B)=\dfrac{P(A\cap B)}{P(B)}$

$P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435$

d) $P (B|A)=\dfrac{P(A\cap B)}{P(A)}$

$P (B|A)=\dfrac{0.10}{0.40}=0.25$

8 0

3 years ago