It should be -v3
Hope this helps
The juice container that is 1 gallon
Answer:
Yuri is not correct.
Step-by-step explanation:
Given expression is q(x) = 6x³ + 19x² - 15x - 28
If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0
Similarly, for x =
,

= 
= 
= 
= 
=
≠ 0
Therefore, Yuri is not correct. x =
can not be a root of the given expression.