Problem 11
<h3>Answer: -4x^2 - 6 (choice 3)</h3>
Work Shown:
P = 4x^2-x+1
Q = -6x^2+x-4
P+Q = sum of P and Q
P+Q = (4x^2-x+1)+(-6x^2+x-4)
P+Q = (4x^2-6x^2)+(-x+x)+(1-4)
P+Q = -2x^2+0x-3
P+Q = -2x^2 - 3
2*(P+Q) = twice the sum of P and Q
2*(P+Q) = 2*(-2x^2 - 3)
2*(P+Q) = 2(-2x^2) + 2(-3)
2*(P+Q) = -4x^2 - 6
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Problem 12
<h3>Answer: 6x^3 + 4x^2 - 34 (choice 1)</h3>
Work Shown:
y = 3x^3 + x^2 - 5
z = x^2 - 12
2(y+z) = 2(3x^3 + x^2 - 5 + x^2-12)
2(y+z) = 2(3x^3 + 2x^2 - 17)
2(y+z) = 2(3x^3) + 2(2x^2) + 2(-17)
2(y+z) = 6x^3 + 4x^2 - 34
All sides of the squares are congruent. This means that when solving for area:
base x height
the base and height would be the same length, 6.25
Multiply
6.25 x 6.25 = 39.0625
39.0625 ft² should be your answer (if i'm thinking of significant digits correctly)
If it should be a whole number, then 39 ft² is your answer
hope this helps
2x + 2(x + 2) = 24
2x + 2x + 4 = 24
4x = 24 - 4
4x = 20
x = 20/4
x = 5
The value of x that holds true for the equation is : x = 5.
So the width of the rectangle is 5 inches and the length is (x + 2 = 5 + 2) = 7 inches
Answer:
0.48.
Step-by-step explanation:
There are 2 ways that a tail lands once:-
Tail + head or
head + tail.
Prob(Tail on one throw) = 0.4
Prob(Head on one throw) = 1 - 0.4 = 0.6.
Prob(Tail first then head) = 0.4 * 0.6 = 0.24
Head then tail has the same probability (0.6*0.4).
So the requred probability = 0.24 + 0.24
= 0.48.
