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rewona [7]
2 years ago
14

Think of a situation in the real world where a relationship occurs between two sets. For example, I could list several different

people and then list their birthdays. I could then form a relationship between these sets. First, illustrate the relationship using arrows. Then determine if the relationship is a function or not. State why?
Mathematics
1 answer:
Alla [95]2 years ago
8 0

Answer:

See Explanation

Step-by-step explanation:

Required

Determine if a real life situation is a function or not

I will give 2 instances

(1) Students and their ID

The relationship is as follows:

Student 1 -----> ID-1

Student 2 -----> ID-2

Student 3 -----> ID-3

Student 4 -----> ID-4

---------

----

--

Student n -----> ID-n

The above is a function because every student has a unique student ID.

In fact, the relation is a one-on-one function because no two students will have the same ID

(2) People and their year of birth

The relationship is as follows:

Person 1 -----> 2000

Person 2 -----> 2001

Person 3 -----> 2002

Person 4 -----> 2001

---------

----

Person n -----> 2005

The above is not a function because there is a possibility that a more than one person will have the same year of birth.

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3a-8a>-20 help I suck at math ​
vazorg [7]

Answer:

Step-by-step explanation:

3a-8a>-20

-5a>-20

a>-20/-5

a>4

5 0
2 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
Quick algebra 1 assignment for 50 points!
Sergeeva-Olga [200]

The example on direct variation is illustrated below based on the information given.

<h3>How to illustrate the direct variation?</h3>

An example will be:

When x = 2, y = 10. Find the value of y when x is 6.

In this case, this will be calculated thus:

y = kx

10 = 2k

k = 10/2

k = 5

Since y = kx.

y = 5 × 6

y = 30

The value of y is 30.

Learn more about variation on:

brainly.com/question/25215474

#SPJ1

3 0
1 year ago
I think I'm struggling to find the inverse for this one:
USPshnik [31]
Recall that the derivative of a constant is 0.

\bf y=x^2-4x+4\implies y=(x-2)^2\implies \stackrel{inverse}{x=(y-2)^2}&#10;\\\\\\&#10;\sqrt{x}=y-2\implies \sqrt{x}+2=y\implies x^{\frac{1}{2}}+2=y&#10;\\\\\\&#10;\cfrac{1}{2}x^{-\frac{1}{2}}+0=\cfrac{dy}{dx}\implies \cfrac{1}{2}x^{-\frac{1}{2}}=\cfrac{dy}{dx}
5 0
3 years ago
What is the equation of a line passing through the points (-3,<br> -2) and (2, 0)?
Lostsunrise [7]

Answer:

y=0.400x+-0.800

Step-by-step explanation:

Given the following question:

point A = (-3, -2)
point B = (2, 0)

To write the equation of the line that passes through two points we have to write the points in slope intercept form.

Formula for slope intercept:

y=mx+b

M is equal to the slope of the two points, so first we need to fine the slope of the two points.

(-3,-2)=(x1,y1)
(2,0)=(x2,y2)

m=\frac{y2-y1}{x2-x1}
m=\frac{0--2}{2--3} =\frac{2}{5}
m=\frac{2}{5} =0.400

y=mx+b
y=-2
m=0.400
x=-3
-2=0.400(-3)+b
0.400\times-3=-1.20
-2+1.2=-0.800
b=-0.800

y=0.400x+-0.800

Hope this helps.

7 0
2 years ago
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