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Nady [450]
3 years ago
11

The domestic cat genome contains 2.9×109 base pairs. The length of linker DNA in mammals is 50 base pairs. Approximately how man

y nucleosomes are required to organize the 10-nm-fiber structure of the genome?
Biology
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

Number of nucleosomes in 2.9 * 10^9bp is equal to 1.47 * 10^7

Explanation:

For wounding one nucleosome, total length of DNA required is equal to 146 bp

The length of  linker DNA in mammals is equal to 50 bp

Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length

= 146 + 50\\= 196bp

Thus, in 196bp length of DNA, the total number of nucleosomes is equal to 1

Thus, number of nucleosomes in 2.9 * 10^9bp is equal to

\frac{2.9* 10^9}{196} \\1.47 * 10^7

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Answer:

Explanation:

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"nonrecombinant gene, recombinant plasmid with vgp gene,", recombinant plasmid but no vgp gene-----------------------will grow in both media".

it means Plasmid have ampicillin resistance gene. So if we use medium with ampicillin so it will allow the growth of only those bacterai which have transformed plasmid (containing amp resistance gene).

 so having gene or not, recombinant or recombinant dosnt matter,  all the other s will grow in both type of medium as far as plasmid is transformed in to it.

3 0
3 years ago
Why no two siblings have the exactly the same combination of random fertilization
Karo-lina-s [1.5K]

Answer:

brothers and sisters don't look exactly alike because everyone (including parents) actually has two copies of most of their genes. And these copies can be different. Parents pass one of their two copies of each of their genes to their kids.

8 0
3 years ago
Según la clasificación de ecosistemas, indica si los siguientes ejemplos de ecosistemas son correctos: Una piscina es un ecosist
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Answer and Explanation:

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  • <em>La pradera es un ecosistema terrestre y natural : VERDADERO. </em>Es terrestre por encontrarse en un espacio continental no inundable, y natural por no ser intervenido por el hombre.
  • <em>Un bosque nativo es un ecosistema terrestre y natural: VERDADERO. </em>Un bosque no es inundable, por lo que se considera netamente terrestre y mientras no sea intervenido por la acción humana es un ecosistema natural.<em> </em>
  • <em>Un arroyo es un ecosistema dulceacuícola y natural: VERDADERO. </em>Entre las posibles ubicaciones de un ecosistema acuático, se hayan aquellos que se encuentran en un medio de agua dulce, tales como arroyos, lagos, ríos, entre otros. Al no ser alterado por el hombre, se lo considera también un ecosistema de origen natural.    <em> </em>
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3 0
3 years ago
An ionic bond occurs when _____
miss Akunina [59]
A non-metal atom receives electrons from a metal atom
8 0
3 years ago
You sampled 1000 individuals from a population of mosquitoes to test whether they are in Hardy-Weinberg Equilibrium for a gene D
Marysya12 [62]

Answer:

The population is not following the Hardy-Weinberg equilibrium.

Explanation:

Hardy-Weinberg  proposed that the population will remain in the equilibrium if they are not affected with the external natural force like genetic drift, mutation and many others. The gene pool of a population will remain in equilibrium state for generations.

The mathematical expression for the Hardy-Weinberg are

Genotypic frequency is p²+q²+2pq=1

Allele frequency is p+q=1

where p-dominant allele,

q-recessive allele

Therefore,calculating expected frequency of allele q,

q² (recessive genotype)-  q²+2pq/1000

= 22+188/1000

=210/1000

= 0.21

q= 0.45

Calculating expected frequency of allele p,

Using p+q=1

p=1-q

p= 0.55 (expected)

Calculating observed value of frequency of p,

p²= p²+2pq/1000

= 790+188/1000

= 978/1000

= 0.978

p = 0.988 (observed)

Since the expected frequency does not match the observed frequency therefore the population is not under the Hardy-Weinberg equilibrium and the gene pool is disturbed.

4 0
3 years ago
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