Answer:
Final answer is 
and 
.
Step-by-step explanation:
Given equation is 
Now we need to find the solution of in given interval ![[0, 2\pi ]](https://tex.z-dn.net/?f=%5B0%2C%202%5Cpi%20%5D)
.
which gives and in the given interval.
Hence final answer is and .
The answer should be 5 over 4
Answer: x⁴y²⁰
Step-by-step explanation: Distribute the exponent ⁴ over the parentheses
(x y⁴)⁴ becomes x⁴y¹⁶ (multiply exponents)
then take the 4th root of y¹⁶ (divide the exponent of the radicand by the index) ⁴√y¹⁶ becomes y⁴
Then multiply the factors. Add exponents
x⁴y¹⁶ * y⁴ becomes x⁴y²⁰
Answer: Probability P = 1/1716
Step-by-step explanation:
Definition
For permutation ( order is important)
nPr = n!/(n-r)!
Given;
Total number of members in the committee = 13
Total number of members to be selected = 3
Since order is important in this case.
The total number (Tt) of possible ways of selecting three executives from the committee members is given as
Tt = 13P3 (since order is important)
Tt = 13!/(13-3)!
Tt = 13!/10!
Tt = 1716
The probability P of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions is equal to
P = number of favourable outcomes/ number of possible outcomes
Number of favourable outcomes = 1 (i.e 1×1×1 = 1) one option for each post.
Number of possible outcomes = Tt = 1716
P = 1/1716
Answer:
P( x = 2) = 0.4
Or 40%
Step-by-step explanation:
Given that wildcat has 0.5 probability of winning if they play nine times
Probability = possible outcomes ÷ required outcome
The required outcome = 9
Probability = 0.5
Let calculate the possible outcomes
Possible outcomes = 0.5 × 9 = 4.5 games
the probability that the Wildcats win two of the games will be
P( x = 2) = 2/4.5 = 0.44
Or 44%
