Answer:
A product of factors is zero if and only if one or more of the factors is zero. That is, if ab = 0, then either a = 0 or b = 0 (or both).
Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both. (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.
Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.
Answer:
Here's the answer hope it helps!!
<u>√(a^6b³)</u> = <u> a³√b³ </u><u /> = <u>a³√b³</u> = <u>a³√b³</u>
98 √(49 × 2) √49√2 7√2
3/5 + 3/20
=12/20 + 3/20
=15/20
1 - 15/20
=20/20 - 15/20
=5/20
=1/4
Step-by-step explanation:
x={m,n,q,r}
Since, the set x contains 4 elements
Therefore,
n(x)=4
Again,
y={q,r,a,b}
Since, the set y contains 4 elements
Therefore,
n(y)=4
