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tatuchka [14]
3 years ago
12

which postulate or theorem can be used to show that all 3 center triangles in the Antigua and Barbuda flag are similar? A. ASA s

imilarity theorem B. SSS similarity theorem C. SAS similarity theorem D. AA similarity postulate
Mathematics
2 answers:
Damm [24]3 years ago
7 0
A. ASA similarity theorem
B. SSS similarity theorem 
gladu [14]3 years ago
4 0

Answer:

B. SSS similarity theorem

Step-by-step explanation:

The answer is SSS similarity theorem or the side side side theorem (If the lengths of the corresponding sides of two triangles are proportional, then the triangles must be similar.)

So, the postulate or theorem that can be used to show that all 3 center triangles in the Antigua and Barbuda flag are similar is SSS similarity theorem.

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The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard de
Sergio [31]

To solve this problem, we use the formula:

z = (x – u) / s

where z is the z score value which can be obtained from the tables, x is the sample value, u is the mean = 6.3 min, and s is the std dev = 2.2 min

 

at P value = 0.90, the z = 1.28, finding for x:

x = z s + u

x = 1.28 * 2.2 + 6.3

x = 9.116

 

at P value = 1.0, the z = 3.49, finding for x:

x = z s + u

x = 3.49 * 2.2 + 6.3

x = 13.978 ~ 14

 

Therefore the longest 10% calls last about 9.1 minutes to 14 minutes

3 0
3 years ago
If a= 2,b= -1,c= -3 and d = -2 evaluate the following Q1. ab-3b+4d , Q2. 5abd+3bc-2ax and Q3. 2(ab)^2+bc^2​
Serggg [28]

Answer:

the answer for question 1 is -7

8 0
3 years ago
How do you find this answer
AURORKA [14]
You have to find the slope and where it intercepts at 
3 0
3 years ago
Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
I WILL MARK BRAINIEST IF CORRECT!
Lunna [17]

Answer:

I believe I would be the last one D

8 0
3 years ago
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