We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
Answer:
The correct answer is:
(a) 0.54
(b) 0.0385
Step-by-step explanation:
Given:
Restaurant tax,
p = 0.54
Sample size,
n = 168
Now,
(a)
The mean will be:
⇒ μ 
(b)
The standard error will be:
= ![\sqrt{[\frac{p(1-p)}{n} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%5D%7D)
= ![\sqrt{[\frac{(0.54\times 0.46)}{168} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B%280.54%5Ctimes%200.46%29%7D%7B168%7D%20%5D%7D)
= ![\sqrt{[\frac{(0.2484)}{168} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B%280.2484%29%7D%7B168%7D%20%5D%7D)
= 
Answer:
The letter P represents 1/8 on the number line
Step-by-step explanation:
Answer: no change, or 0%
Step-by-step explanation:
lcm 4, 7: 28
$210:28 tickets
$210:28 tickets
$210=$210, no change
Answer:
y=4/3x+2.5
Step-by-step explanation:
im not 100% sure if i get it wrong reply
