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3 years ago

14

What's 2x + 3y = 1,470 in slope intercept form?

1 answer:

dedylja [7]3 years ago

4 0

Well I don't know !
Let's get together and solve that thing for 'y' .

   2x + 3y =   1,470

Subtract 2x from each side: 3y =   -2 x + 1,470

Divide each side by 3 :    y =   -2/3 x +   490

There you are.
If you graph that equation, the slope is -2/3
and the y-intercept is 490 .

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$\textsf{Point-slope form}: \quad \sf y-2=4(x+1)$

$\textsf{Slope-intercept form}: \quad \sf y=4x+6$

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Step-by-step explanation:

<u>Given information</u>:

Slope = 4
Point on line = (-1, 2)

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$\sf y-y_1=m(x-x_1)$

(where m is the slope and (x₁, y₁) is a point on the line)

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$\implies \sf y-2=4(x+1)$

<u>Slope-intercept form</u><u> of a linear equation</u>:

$\sf y=mx+b$

(where m is the slope and b is the y-intercept)

Substitute the given slope and point into the formula and solve for b:

$\implies \sf 2=4(-1)+b$

$\implies \sf b=6$

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$\sf y=4x+6$

<u>Standard form</u><u> of a linear equation</u>:

$\sf Ax+By=C$

(where A, B and C are constants and A must be positive)

Rearrange the found slope-intercept form of the equation into standard form:

$\implies \sf y=4x+6$

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