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DedPeter [7]
3 years ago
10

Find sin2z, cos2x and tan2x if cosx=(3/5) and x is in quadrant 1

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
         cos(x) = ³/₅
cos⁻¹[cos(x)] = cos⁻¹(³/₅)
                 x ≈ 53.13

sin(2x) = sin[2(53.13)]
sin(2x) = sin(106.26)
sin(2x) = 0.960001

cos(2x) = cos[2(53.13)]
cos(2x) = cos(106.26)
cos(2x) = -0.27999657

tan(2x) = tan[2(53.13)]
tan(2x) = tan(106.26)
tan(2x) = -3.428617001
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The mean value theorem basically asserts that there is at least one place where the tangent to the arc is parallel to the secant through its ends for any given planar arc between two endpoints. One of the most significant findings in real analysis is this one.

Here, we have

A. Therefore, according to the theorem, the hypothesis for the mean value theorem for the given function must be

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g is differentiable on the open interval (0,8)

Hence, options fourth and sixth are rightly selected.

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We will see this graphically, by first drawing the line joining the endpoints and then see is parallel lines where they intersect the graph

y = g(x) 0 1 2.2 6.5

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To learn more about the mean value theorem from the given link

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  Vertical stretch by a factor of 6

Step-by-step explanation:

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Answer:

see below

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Answer:

Step-by-step explanation:

From the graph attached,

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