A1=12
d=a2-a1→d=2-7=-5
a33=a1+32d→a33=12+32(-5)→a33=12-160=-148
The answer would be:
The x-intercept of the boundary line is (-3/2, 0).
The area below the line is shaded.
The slope of the line should be 2/3. The area below the line shaded because the function using y<.....
Coordinate 2,3 doesn't fulfill the function.
y < 2/3x + 1
3 < 2/3(2)+1
3< 4/3+1
3< 2.3 ---->false
X intercept is when the y variable is zero. If you put it to the equation
y = 2/3x + 1
0= 2/3x+1
2/3x= -1
x= -3/2
Answer:
A
Step-by-step explanation:
The mean is a good measure of central tendency because it takes into account all of the data compared to other. One of the instance where the mean is not good measure is when there are outliers ( extreme values) in the data in this case the median is better. In the scenario in the question the data set is nearly symmetrical therefore the mean is best central tendency measure to use
Answer:
x=38/5
Step-by-step explanation:
distribute
Add 2 to both sides of the equation
Simplify
Answer:
Let the sides be a and b
a^2 + b^2 = c^2 = 29^2 = 841
a^2 + (a + 1)^2 = 841
a^2 + a^2 + 2 a + 1 = 841
2 a^2 + 2 a = 840
a (a + 1) = 420
21 * 20 = 420 trial and error
So the sides are 20 and 21
20^2 + 21^2 = 29^2